If ( x+ 5 ) is a zero of x^3+2x^2-14x+k+2 , then find k
Answers
Answered by
0
Step-by-step explanation:
if x+5 is a factor of f(x) then remainder f(-5)=0
-5³+2×5²+14×5+k+2 =0
-125+50+70+k+2 =0
-3+k=0
k=3
Answered by
1
Step-by-step explanation:
p( -5) = (-5)³ + 2(-5)² -14(-5) + k + 2 = 0
= -125 + 50 + 60 + 2 +k = 0
= k = 14
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