Question

If x=5 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Answer:

Answer is 19/10

Step-by-step explanation:

Suppose

p(x) = x²-2kx-6=0

x= 5 is one root of the quadratic equation

Remainder = p(5) = 0

=> p(5)=0

=> (5)²-2k(5) - 6 = 0

=> 25-10k-6=0

=> -10k=6-25

=> - 10k = -19

=> k=19/10