Question

If x=5 is one root of the quadratic equation x²-5kx-6=0 then find value ok k.​

Answer 1

Answer:

10/25

Step-by-step explanation:

We have-

p(x) = x²-5kx-6=0

x= 5 is one root of the quadratic equation

Remainder = p(5) = 0

=> p(5)=0

=> (5)²-5k(5) - 6 = 0

=> 25-25k-6=0

=> -25k=6-25

=> - 25k = -19

=> k=19/25

Answer 2

Step-by-step explanation:

put value of x in equation

hence

25-25k-6=

19-25k=

25k=19

hence

k=19/25