Question

If x=5 is root of equation kx2-14x-5=0 then find the value of k​

Answer 1

Answer:

K=3

Step-by-step explanation:

K*5²-14*5-5=0

25k-70-5=0

25k=75

K=75/25

K=3

Answer 2

Answer:

$\huge\underline\bold\red{Answer!!}$

$Given,$

x=5 is one of the root of the equation kx²−14x−5=0

−14x−5=0then, it should satisfy the equation

$k(5)2−14(5)−5=0</em></p><p></p><p></p><p><em>\</em><em>\</em><em>= > k = \frac{14 (5) + 5}{5 {}^{2} }$

$= > k = \frac{75}{25}$

$= > k = 3$