Math, asked by Maline, 1 year ago

If x= 5 - root 21 /2, find the values of (j) x+1/x (ii) x^2+1/x^2

Answers

Answered by abhi178
31
x = (5 - √21)/2

1/x = 2/(5 -√21)
=2(5 + √21)/(5 -√21)(5 + √21)
= (5 + √21)/2

hence,
x + 1/x = (5 -√21)/2 + (5+√21)/2 =5

x² + 1/x² = (x + 1/x)² -2x.1/x
= (x + 1/x)² -2
=(5)² -2
= 23
Answered by malo5912
7

Step-by-step explanation:

I am not getting beyond this please help

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