if x=5 then x+=(++x) +(++x) +(x--).,
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Explanation:
Using what I know of post-increment and pre-increment in programming, I would use the following reasoning:
++x, you increment the number contained in ‘x’ and then use the variable itself for whatever reason.
x++, you use the variable itself for whatever reason, and then you increment the number contained in ‘x’.Let’s solve your equation now:
x = 3;
x = ++x + (++x);
++x would increase ‘x’ by one and use this value. If you add 1 to the current value of x, which is 3, then you have 4.
x = 4 + (++x);
++x would increase ‘x’ by one again and use (again) this value. If you add 1 to the current value of x, which is 4, then you have 5.
x = 4 + (5);
Sum the remainders, and the solution of your question would be:
x = 9;
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2
Answer:
9
Explanation:
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