Math, asked by anisha13139, 8 days ago

if(x^5×x^-2)^2=64 what is the value of x^-4?​

Answers

Answered by AayushJp
1

Answer:

x^-4 = 1/16 or 0.0625

Step-by-step explanation:

Solving the bracket first ,

x^5 * x^-2 = x^3      (5 - 2 = 3 )

Now,

(x^3)^2= x^6

x^6 = 64

x = 2                        (2^6 = 64 )

So,

x^-4 can be written as 1/x^4

Hence ,

By substituting x by 2 , we get ,

1/2^4 = 1/16 or 0.0625

Answered by Anonymous
1

Answer

Answer

 \sf \blue{Given }\\  \\  \boxed{ \rm \: x^5×^{-2}=64}\\  \\  \\  \\ (x5×x−2)2=64 \\  \\ (x {}^{5 - 2} ) {}^{2} = 2  {}^{6} \\  \\ (x5−2)2=26 \\  \\ x {}^{3 \times 2} = 2 {}^{6 } \\  \\ x { }^{6} = 2 {}^{6}x6=26 \\  \\ x = 2x=2 \\  \\  \bf{A/Q} \\  \\=  > x {}^{4} \\  \\  =  > 2 {}^{4} \\  \\  =  > 16

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