Math, asked by kumarsachin32512, 5 months ago

if (x^5× x^-2)^2 = 64, what is x​

Answers

Answered by Anonymous
16

Step-by-step explanation:

I’m assuming that you mean: 2^(-5) = 64.

2x−5=64=82=26

Multiplying both sides of the equation by x5 , we have:

2=26x5

Dividing both sides by 26 , we have:

2−5=x5

Taking the principal fifth root of both sides:

2−1=x

Answer: x = 0.5

There are, of course, four other answers that involve an ‘imaginary’ component. These are approximately:

0.15451 ± 0.47553 i

-0.40451 ± 0.29389 i

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