if (x^5× x^-2)^2 = 64, what is x
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Step-by-step explanation:
I’m assuming that you mean: 2^(-5) = 64.
2x−5=64=82=26
Multiplying both sides of the equation by x5 , we have:
2=26x5
Dividing both sides by 26 , we have:
2−5=x5
Taking the principal fifth root of both sides:
2−1=x
Answer: x = 0.5
There are, of course, four other answers that involve an ‘imaginary’ component. These are approximately:
0.15451 ± 0.47553 i
-0.40451 ± 0.29389 i
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