Question

if x=5,y=2find the value of :- (x^y+y^x)^-1​

Answer 1

Answer:

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Answer 2

given,

$x = 5$

$y = 2$

then,

${({x}^{y} + {y}^{x})}^{ - 1} = \frac{1}{ {x}^{y} + {y}^{x} }$

$= \frac{1}{ {5}^{2} + {2}^{5} }$

$= \frac{1}{25 + 4}$

$= \frac{1}{29}$