Question

if x =5andy=2 find the value of (x^x+y^y)^-1​

Answer 1

Answer:

(3125+4)^-1

= 3129^-1

= 1/3129

Answer 2

Answer:

1/(3129)

Step-by-step explanation:

If x=5

x^x=5^5=3125

If y=2

y^y=2^2=4

x^x+y^y=3125+4=3129

(3129)^(-1)=1/(3129)

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