If x=5t2 +7t+3m, then find the velocity at t=2sec, where x is the displacement?
Answers
Answered by
17
Answer:
x=5t
2
+18t
(1)v=
dt
dx
=10t+18
att=2s,v=10×2+18=38m/s
(2)Average,velocity=
time
displacement
att=2,x=5(2)
2
+18×2=56m
t=3,x=5(3)
2
+18×3=99m
Averagevelocity=
3−2
99−56
=43 m/s
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Answered by
3
Answer:
given : x = 5t² + 7t + 3
to find velocity at t = 2 sec
velocity V = dx/dt = 10t + 7
therefore V (at t = 2 sec) = 10 × 2 + 7
=> 27 m/sec
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