Question

If x = 6+6t-3t^2, find the value of dx/dt

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Answer 1

Answer:

hey this is differentitation

Step-by-step explanation:

1) If y = x^n,

dy/dx = nx^n-1

this is the basic rule we use here

-3t^2 = 2*3t^2-1

zero is the value of constant here 6 is constant

differenriation of t with respect to itself t gives value 1

therfore 6t=6

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