Math, asked by anandjai5253, 6 months ago

if x=6+√7,then find the value of x²+1/x²​

Answers

Answered by krishna2000fzd
1

x=6+√7

x²+1/= (6+7)²/1/(6+7)²

36+7 / 1 / 36+7

(36+7)-(36+7)/1

=0

Answered by Anonymous
0

3278+24√7

3278+24√7 43-12√7

Step-by-step explanation:

x=6+√7

1/x=1/(6+√7)

=1(6-√7)/(6+√7)(6-√7)

=[6-√7]/[(6)²-(√7)²]

=(6-√7)/36-7

=(6-√7)/29

We know that,

(x+1/x)²=x²+1/x²+2

x²+1/x²=(x+1/x)²-2

={(6+√7+1/(6-√7)/29}²-2

={(6+√7)+29/ (6-√7)}²-2

= {[(6+√7)(6-√7)+29]/ (6-√7)}²-2

=(36-7+29)² -2

( 6-√7)²

= 58². -2

36+7-12√7

= 3364. -2

43-12√7

= 3364-2(43-12√7)

43-12√7

=3364-86+24√7

43-12√7

=3278+24√7

43-12√7

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