If x+6 is a factor of P(x) = x³+ 3x ² +4+k. find the value of k
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Answered by
1
Answer:
k=104
Step-by-step explanation:
since x+6 is a factor of P(x)
using factor theorem,
x+6 = 0
therefore, x=-6
putiing x=-6 in P(x)
P(-6) = (-6)³ + 3 × (-6)² + 4 + k = 0
-216 +( 3 × 36 )+ 4+ k =0
-216 + 108 + 4+k=0
-216 + 112 +k=0
k - 104 = 0
k = 104
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Answered by
0
Answer:
132
Step-by-step explanation:
x+6 = 0
==> x = -6
Now, p(x) = x<3> + 3x<2> + 4x + k
= (-6)<3> + 3(-6)<2> + 4(-6) + k
= -216 +3(36) - 24 + k
= -216 + 108 - 24 + k
= k = -132
Also given that (x+6) is a factor of p(x)
So, P(x) = 0
k-132 = 0
k = 132
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