if (x-6) is a factor of x^3+ax^2+bx-b and a-b=7 find the value of a and b
Answers
Answered by
151
Given that x - 6 is a factor of f(x). SO, substitute x =6 in the given polynomial equation
x^3+ax^2+bx-b = 0
put x = 6
6^3 + a (6^2) + 6b - b =0
216 + 36 a + 5b = 0
SO, 36 a + 5b = -216
also, given a - b = 7
so, 5a - 5b = 35
add these both equations
5b is cancelled
41 a = -181
so, a = -181/41 and b = -468/41
x^3+ax^2+bx-b = 0
put x = 6
6^3 + a (6^2) + 6b - b =0
216 + 36 a + 5b = 0
SO, 36 a + 5b = -216
also, given a - b = 7
so, 5a - 5b = 35
add these both equations
5b is cancelled
41 a = -181
so, a = -181/41 and b = -468/41
Answered by
28
Answer:
a = -181/41 and b = -468/41
Step-by-step explanation:
Given that x - 6 is a factor of f(x). SO, substitute x =6 in the given polynomial equation
x^3+ax^2+bx-b = 0
put x = 6
6^3 + a (6^2) + 6b - b =0
216 + 36 a + 5b = 0
SO, 36 a + 5b = -216
also, given a - b = 7
so, 5a - 5b = 35
add these both equations
5b is cancelled
41 a = -181
so, a = -181/41 and b = -468/41
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