Question

If (x +6) is a factor of x2-x + p, then the value of p is​

Answer 1

Step-by-step explanation:

For finding the remainder we need to use remainder theorem

For finding the remainder we need to use remainder theoremLet p(x)=x

For finding the remainder we need to use remainder theoremLet p(x)=x 2

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−p

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−p

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p)

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p 2

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p 2 −p

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p 2 −p 2

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p 2 −p 2 +3−p=0

For finding the remainder we need to use remainder theoremLet p(x)=x 2 +px+3−pAs x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).So, x+p=0or, x=−pAs, −p is a zero of p(x), so,p(−p)=(−p) 2 +p(−p)+3−p=0⇒p 2 −p 2 +3−p=0or, p=3

Answer 2

Step-by-step explanation:

hope it helps pls follow pls