If (x-6) is a factor of (x3+ax2+bx-6) and a-b=7 then find a and b
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Answered by
1
Step-by-step explanation:
x - 6 = 0
x = 6
So , (6)³ + a(6)² + b(6) - 6 = 0
216 + 36a + 6b - 6 = 0
36a + 6b = -210
6a + b = -35 --------(1)
a - b = 7 ------(2) ( given )
from equation (1) + (2)
7a = -28
a = -4
then b = -35 - 6(-4) = -35 + 24 = -11
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