if (x-6) is a factor of x3+ax2+bx-b=0 and a-b=7,find the value of a and b
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8
Answer:
a = -181/41
Step-by-step explanation:
as x-6 is a factor of x3+ax2+bx-b=0 ,substitute x=6 in x3+ax2+bx-b=0
===>6³+a×6²+b×6-b=0
===>216+36a+5b = 0 ----1
as a-b =7 ==> 5a-5b = 35 -----2
so eq 1 + eq 2
gives 216 +41a = 35
so a = -181/41
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