If x+6 is factor of p (x)
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1
X+6=0
X=-6
p(-6)=(-6)³+3(-6)²+4(-6)+k
= -216+108-24+k
=-240+108+k
=-132+k
132=k
X=-6
p(-6)=(-6)³+3(-6)²+4(-6)+k
= -216+108-24+k
=-240+108+k
=-132+k
132=k
Answered by
0
Given equation
x^3 + 3x^2 +4x+k = 0
(x+6) is a factor of the equation
(x+6)=0; x = -6 ... substituting it in the equation
(-6)^3 + 3(-6)^2 +4(-6)+k = 0
-216 + 3(36) -24 + k = 0
-216 + 108 -24 + k =0
-132 + k = 0
k = 132
The equation is
x^3 + 3x^2 +4x+132 = 0
x^3 + 3x^2 +4x+k = 0
(x+6) is a factor of the equation
(x+6)=0; x = -6 ... substituting it in the equation
(-6)^3 + 3(-6)^2 +4(-6)+k = 0
-216 + 3(36) -24 + k = 0
-216 + 108 -24 + k =0
-132 + k = 0
k = 132
The equation is
x^3 + 3x^2 +4x+132 = 0
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