Question

If x=6 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Answer:

5/2

Step-by-step explanation:

Let

p(x) = x²-2kx-6=0

x= 6 is one root of the quadratic equation

Remainder = p(6) = 0

=> p(6)=0

=> (6)²-2k(6) - 6 = 0

=> 36-12k-6=0

=> -12k=6-36

=> - 12k = -30

=> k=30/12

=> k=5/2

Answer 2

${x}^{2} - 2kx - 6 = 0 \\ {6}^{2} - 2k(6) - 6 = 0 \\ 36 - 12k - 6 = 0 \\ - 12k + 36 - 6 = 0 \\ - 12k + 30 = 0 \\ - 12k = - 30 \\ k = - 30 \div - 12 \\ k = 5 \div 2$

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