if (x+6) is the GCD of (x^2+ax-13) and (x^2-x-42) find the value of a
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Answer:
Value of a is 23/6.
Step-by-step explanation:
Given: (x+6) is GCD of both (x²+ax-13) and (x²-x-42).
When (x²+ax-13) is divided by (x+6), it leaves the remainder (23-6a).
But (x²+ax-13) is divisible by (x+6). So, it must leave the remainder 0.
⇒ 23-6a = 0
or a = 23/6
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