Question

if (x+6) is the GCD of (x^2+ax-13) and (x^2-x-42) find the value of a​

Answer 1

Answer:

Value of a is 23/6.

Step-by-step explanation:

Given: (x+6) is GCD of both (x²+ax-13) and (x²-x-42).

When (x²+ax-13) is divided by (x+6), it leaves the remainder (23-6a).

But (x²+ax-13) is divisible by (x+6). So, it must leave the remainder 0.

⇒ 23-6a = 0

or a = 23/6

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