Math, asked by aswinrr7, 9 months ago

if (x-6) is the hcf of x² -2x-24 and x²-kx-6 then the value of k is

Answers

Answered by ThinkingBoy
5

(x-6) is HCF of x²-2x-24 and x²-kx-6.

That means, (x-6) is a factor of x²-kx-6

That again means that x = 6 is a zero of the polynomial x²-kx-6.

So, we can write

6² - k×6 - 6 = 0

36 - 6k - 6 = 0

6 - k - 1 = 0

k = 5

Answered by shannonajivarkey
4

Answer:

(x-6) is HCF of x²-2x-24 and x²-kx-6.

That means, (x-6) is a factor of x²-kx-6

That again means that x = 6 is a zero of the polynomial x²-kx-6.

So, we can write

6² - k×6 - 6 = 0

36 - 6k - 6 = 0

6 - k - 1 = 0

k = 5

Step-by-step explanation:

first find the hcf and then you will directly get the value

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