if (x-6) is the hcf of x² -2x-24 and x²-kx-6 then the value of k is
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Answered by
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(x-6) is HCF of x²-2x-24 and x²-kx-6.
That means, (x-6) is a factor of x²-kx-6
That again means that x = 6 is a zero of the polynomial x²-kx-6.
So, we can write
6² - k×6 - 6 = 0
36 - 6k - 6 = 0
6 - k - 1 = 0
k = 5
Answered by
4
Answer:
(x-6) is HCF of x²-2x-24 and x²-kx-6.
That means, (x-6) is a factor of x²-kx-6
That again means that x = 6 is a zero of the polynomial x²-kx-6.
So, we can write
6² - k×6 - 6 = 0
36 - 6k - 6 = 0
6 - k - 1 = 0
k = 5
Step-by-step explanation:
first find the hcf and then you will directly get the value
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