Question

If (x - 6) is the HCF of x2 - 2x - 24 and x2 - kx - 6 then the value of k??❤☺
gd morning everyone koi h ☺​

Answer 1

Answer:

Given that (x−6) is the HCF of 

x2−2x−2y and x2−4x−6(x−6) is factor of both expression

Let f(x1)=x12−2x1−24

and f(x2)=x22−4x2−6

Now f(x1)=f(x2) at (x1=x2=6)

⇒(6)2−2(6)−24=(6)2−4(6)−6⇒0=30−6k⇒6k=30∴k=5

Good vala morning to u❤

take care..

have a nice day..

Answer 2

A very Gud Morning G ❤️❤️

Time and Good Friend Are two things That become More Valueable Then the older one....❤️

Yes , Me Always There For You ❤️