Question

if x=6-root35,then find the value of x^2+1/x^2

Answer 1

Assuming you mean a^2 - (1/a)^2, this is 

(6 - √35)^2 + (1 / (6 - √35))^2 
(36 - 12√35 + 35) + (1 / (36 - 12√35 + 35)) 
(71 - 12√35) + (1 / (71 - 12√35)) 
(71 - 12√35) + [ (71+12√35) / (71 - 12√35)(71+12√35) ] 
(71 - 12√35) + [ (71+12√35) / (5041 - 5040) ] 
(71 - 12√35) + (71+12√35) 
142
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