if x=6,y=-2 and z=3,evaluate
x+y
X²
xy+z
x+2y
Answers
Answered by
0
Answer:
x + y = 4
x² = 36
xy + z = -9
x + 2y = 2
Answered by
0
Answer:
6+-2=4
6*2=36
6×-2+3=-9
6+2×-2=-16
Similar questions