Question

if x=6,y=3,z=2 ,
find the value of
$4xy+x÷4+xz÷3$
​

Answer 1

Answer:

sorry bro i can't do that sorry

Answer 2

Answer:

$= 4xy + x \div 4 + xz \div 3 \\ \\ = 4xy + x \times \frac{1}{4xz} \times \frac{1}{3} \\ \\ = 4 \times 6 \times 3 + \frac{1}{4 \times 6 \times 2} \times \frac{1}{3} \\ \\ = 72 + \frac{1}{144} \\ \\ = \frac{72 \times 144 + 1}{144} \\ \\ = \frac{10369}{144}$

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