Question

If x = (6y + 4) (3y^2 + 4y + 3) then integrate xdy will be :

Answer 1

first multiply (6y+4) *(3y^2+4y+3)

            =18y^3+36y^2+34y+12

     

∫xdy=   18/4 y^4 +36/3 y^3 + 34/2 y^2 + 12y

   

Answer 2

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◆ Answer -

first multiply (6y+4) *(3y^2+4y+3)

            =18y^3+36y^2+34y+12

     

∫xdy=   18/4 y^4 +36/3 y^3 + 34/2 y^2 + 12y

i hope it's help you ⚡