Question

if x=√7+2 then find the value of x2+1\x2​

Answer 1

Ans:- x=√7+2

then, 1/x = 1 / √7 + 2 = 1/ √7 + 2 × √7 - 2 / √7 - 2

= √7 - 2 / 3

Now, (x + 1/x)^2 = √7 + 2 + (√7 - 2)/3

= x^2 + 1/x^2 + 2 = 4√7 - 4

= x^2 + 1/x^2 = 4√7 - 6

= x^2 + 1/x^2 = 2(2√7 - 3)

here is your answer

hope it will help you