If (x + 7)³ + (2x + 8)³ +(2x + 3)³ = 3(x + 7) + (2x + 8) +(2x + 3), then what is the value of x?
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Answer:
568+;_#+)8_£¢¥®=[¶[ cgxxc explain correctly
Answered by
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Answer:
first question is wrong
the question in original format
a^3 +b^3+c^3 -3abc =(a+b+c)(a^2+b^2 +c^2 -ab-bc-ca)
to become a^3+b^3+c^3 = 3abc ; either a+b+c= 0 (or) a^2 +b^2 +c^2- ab-bc-ca =0
{ a^2 +b^2 +c^2- ab-bc-ca =0 is a quadratic equation, this might not be-0}
so a+b+c =0 ; x+7+2x+8 +2x+3 = 0
5x + 18 = 0 ;
so x = -3.6
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