If x^7+3x^5+100 is divided by x-1 then find the remainder
AshuAbhishek11:
104
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Answered by
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Hi friend!!
Let x-1=0
x=1
To find the remainder when
is divided by x-1, you simply have to substitute x=1 in the polynomial
→ (1)^7+3(1)^5+100
=1+3+100
=104
104 is the remainder.
I hope this will help u ;)
Let x-1=0
x=1
To find the remainder when
is divided by x-1, you simply have to substitute x=1 in the polynomial
→ (1)^7+3(1)^5+100
=1+3+100
=104
104 is the remainder.
I hope this will help u ;)
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