Question

if x^7+ 3x^5 +100 is divided by x-1,then find the remainder

Answer 1

we will find the remainder by the remainder theorem

First we will find the zero of divisior

x-1=0
x=1

p(x)=x^7+3x^5+100

Put x=1

p(1)=1^7+3*1^5+100

p(1)=1+3+100

p(1)=104

Hence, The remainder will be 104