Question

If x = 7 + 4√3 and xy = 1 then find the value of 1/x squre + 1/y squre​

Answer 1

$answer$

$x = 7 + \sqrt{3}$

$xy = 1$

$so \: {} \frac{1}{x} ^{2} = {}^ \frac{1}{ {x}^{2} } {2} + \frac{1}{y}$

$ans = \frac{1}{ {x}^{2} } {}^{2} + \frac{1}{y}$

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Answer 2

answer

x = 7 + \sqrt{3}x=7+

3

xy = 1xy=1

so \: {} \frac{1}{x} ^{2} = {}^ \frac{1}{ {x}^{2} } {2} + \frac{1}{y}so

x

1

2

=

x

2

1

2+

y

1

ans = \frac{1}{ {x}^{2} } {}^{2} + \frac{1}{y}ans=

x

2

1

2

+

y

1