If x = 7+ 4√3 and xy = 1, then x² + y² is equal to
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THE CORRECT QUESTION IS
If x = 7+ 4√3 and xy = 1, then 1/x² + 1/y² is equal to?
QUESTION FROM RD SHARMA CLASS 9 EDITION 2019 CHAPTER RATIONALISATION PAGE NUMBER 3.17 QUESTION 11
Solution
Given
x=7+4√3
xy=1
To Find
1/x²+1/y²
Explanation
x=7+4√3
xy=1
y=1/x
y=1/7+4√3
y=1×7-4√3/7+4√3×7-4√3
y=7-4√3/(7)²-(4√3)² {(a+b)(a-b)=a²-b²}
y=7-4√3/49-48
y=7-4√3/1
y=7-4√3
1/x²+1/y²
1/1/y²+x² {x=1/y, 1/y=x}
=y²+x²
=(7-4√3)²+(7+4√3)²
=(7)²+(4√3)²-2×7×4√3+(7)²+(4√3)²-2×7×4√3
{a+b)²=a²+b²+2ab} {(a-b)²=a²+b²-2ab}
=49+48-56√3+49+48-56√3
=97+97
=194
Hence 1/x²+1/y²=194
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