Question

If X=7+4√3 then find the value of √X+1÷√X​

Answer 1

Answer:

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Step-by-step explanation:

$(\sqrt{x} + \frac{1}{\sqrt{x}})^2\\\\= x + 2 + 1/x \\\\= (7+4\sqrt{3})+2+\frac{1}{7+4\sqrt{3}} \\\\= (7+4\sqrt{3}) + 2+ (7-4\sqrt{3})\\\\= 16$

∴$\sqrt{x} +\frac{1}{\sqrt{x} } = 4$