Question

if x=[7+4√3 ]then find the value x+1÷x

Answer 1

Heya !!



X = ( 7 + 4 root 3 )




1/X = 1/ ( 7 + 4 root 3 )




1/X = 1/ ( 7 + 4 root 3 ) × ( 7 - 4root3)/(7-4root3)



1/X = ( 7 - 4root 3 ) / ( 7 + root3)(7-4root3)


1/X = ( 7 - 4root3) ( 7)² - (4root3)²



1/X = ( 7 - 4root3) / 49 - 48



1/X = ( 7 - 4root 3 )



Therefore,




X + 1/X = ( 7 + 4root3 ) + ( 7- 4root 3 ) = 14.

Answer 2

Hello



X = ( 7 + 4 root 3 )


1/X = 1/ ( 7 + 4 root 3)


1/X = ( 7 - 4root 3 ) / ( 7 + root3)(7-4root3)

1/X = ( 7 - 4root 3 )



So,




X + 1/X = ( 7 + 4root3 ) + ( 7- 4root 3 ) = 14.