:if x=7+4√3find the value of (x-1/x)^3
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Given x = 7 + 4√3
x = 7 + 4√3
1 / x = 1 / ( 7 + 4√3) rationalize denominator (7 - 4√3)
= (7 - 4√3) / 49 - 48 = (7 - 4√3)
1) x + 1 / x = 7 + 4√3 + 7 - 4√3 = 14.
And √x = √( 7 + 4√3 ) = √ ( √4)2 + (√3)2 + 2x√4x√3 )
√x = √4) + (√3) = 2 + √3 .
⇒ 1 / √x = 1 / ( 2 + √3 ) rationalize denominator (2 - √3) then
⇒ 1 / √x = 2 - √3
2) √x +1 / √x = 2 + √3 + 2 - √3 = 4
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