Question

if x = 7 + 4 root 3 then find the value of x plus one upon x​

Answer 1

this is the required answer..

Answer 2

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$\underline{\large\mathcal\red{Solution}}$

(:)

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$\: \: \: x = 7 + 4 \sqrt{3} \: \: \\ now \: \: \frac{1}{x} = \frac{1}{7 + 4 \sqrt{3} } \\ = > \frac{1}{x} = \frac{7 - 4 \sqrt{3} }{(7 + 4 \sqrt{3})(7 - 4 \sqrt{3} )} \\ = > \frac{1}{x} = \frac{7 - 4 \sqrt{3} }{7 {}^{2} - (4 \sqrt{3}) {}^{2} } \\ = > \frac{1}{x} = \frac{7 - 4 \sqrt{3} }{49 - 48} \\ = > \frac{1}{x} = \frac{7 - 4 \sqrt{3} }{1} \\ = > \frac{1}{x} = (7 - 4 \sqrt{3} )$

therefore:

$(x + \frac{1}{x} ) = 7 + 4 \sqrt{3} + 7 - 4 \sqrt{3} \\ = > (x + \frac{1}{x} ) = 14 \: \: (answer)$

$\large\mathcal\red{hope\: this \: helps \:you......}$