if x=7+√40find the value of√x+1/x
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Answer:
x=7+√40
=7+2√10
=5+2+2√10
=(√5)²+2.√5.√2+(√2)²
=(√5+√2)²
∴√x=√5+√2 (neglecting the negative sign)
1/√x=1/(√5+√2)
=(√5-√2)/(√5+√2)(√5-√2)
=(√5-√2)/(5-2)
=(√5-√2)/3
√x+1/√x
=(√5+√2)+(√5-√2)/3
=(3√5+3√2+√5-√2)/3
=(4√5+2√2)/3
=2(2√5+√2)/3
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