Math, asked by sricharan69, 1 year ago

If x=7+45 and xy = 1 Then
 1\div  {x}^{2}  + 1 \div  {y}^{2}

Answers

Answered by codiepienagoya
0

Simplify:

Step-by-step explanation:

\ Given \ value:\\\\ \ x \ = 7+45 \  \ \ and \ \ \  xy \ = \ 1\\\\\ find:  \  1 \div x^2\ + 1 \div \ y^2\\\\\ Solve:\\\\\rightarrow \ x \ = 7+45 \ = 52 \ and \ xy = 1\\\\\rightarrow \ x \ = 52 \ and \ y = \frac{1}{x}\\\\\therefore  \ x \ = 52 \ and \ y = \frac{1}{52}\\\\ \because \ x^2 \ = \ 2704 \ and \ y^2 = \frac{1}{2,704}\\\\\ Question: \ \ \  1 \div x^2\ + 1 \div \ y^2\\\\\rightarrow \frac{1}{x^2} + \frac{1}{y^2}\\\\\rightarrow \frac{1}{2704 } + \frac{1}{\frac{1}{2704}}\\\\

\rightarrow \frac{1}{2704 } + 2704\\\\\\\rightarrow \frac{1+2704\times2704}{2704 }\\\\\rightarrow \frac{7311617}{2704 }\\\\\rightarrow  2704.00\\

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