If x = 7 – 5 , y = 5 – 3 and z = 3 – 7 , then the value of x3+y3+z3–2xyz is _____________.
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X=7-5, y=5-3,z=3-7 then find the value of x³ +y³+z³-2xyz
This is question
____________________________
Solution
So
(7-5)³+(5-3)³+(3-7)³-(2*7-5*5-3*3-7)
(2)³+(2)³+(-4)³-(2*2*2*-4)
8+8-64-32
16-64-32
16-96
- 80
I hope this will help you
By DEVANSH
This is question
____________________________
Solution
So
(7-5)³+(5-3)³+(3-7)³-(2*7-5*5-3*3-7)
(2)³+(2)³+(-4)³-(2*2*2*-4)
8+8-64-32
16-64-32
16-96
- 80
I hope this will help you
By DEVANSH
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