Math, asked by SJROCKS, 9 months ago

if x=√7+√5, y=√7-√5 find xy and x+y​

Answers

Answered by vanshg28
0

Answer:

x =  \sqrt{7}  +  \sqrt{5}

y =  \sqrt{7}  -  \sqrt{5}

xy = ( \sqrt{7}  +  \sqrt{5} )( \sqrt{7}  -  \sqrt{5} ) =  { \sqrt{7} }^{2}  -  { \sqrt{5} }^{2}  = 7 - 5 = 2

x + y =  \sqrt{7}  +  \sqrt{5}  +  \sqrt{7}  -  \sqrt{5}  = 2 \sqrt{7}

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Answered by tummakeerthana19
0

Answer:

x=root7+root5

y=root7-root5

xy=(root7+root5)(root7-root5)

=(root7)²-(root5)²=7-5=2

x+y=root7+root5+root7-root5

=2root7

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