if x=7 and y=3 is the solution of equations ax+by=18 and bx+ay=12 then a+b=___
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Step-by-step explanation:
It is given that
x=7 and y=3 ,ax+by=18,bx+ay=12
bx+ay=12
(b×7)+(a×3)=12
7b+3a=12
7b=12-3a
b=(12-3a)/7
Now putting the value of b in ax+by=18
(a×7)+(b×3)=18
7a+3b=18
7a+3((12-3a)/7)=18
7a+36-9a/7=18
36-9a+49a=18
36+40a/7=18
36+40a=18×7
36+40a=126
40a=126-36
40a=90
a=90/40
a=9/4
We know that b=(12-3a)/7
b=(12-3×9/4)/7
b=(12-27)/7×4
b=-15/28
Now putting the value of a and b in a+b
=9/4+(-15/28)
=9/4-15/28
=(63-15)/28
=48/28
=12/7
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0
Answer:
3
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