Question

if (x-√7) is a factor of x³-3√7x²+16x-2√7. find all the zeroes of the polynomial.​

Answer 1

Answer:

x=3

x=2 is the answer

Explanation:

STEP

1

:

Equation at the end of step 1

(((x3) - 7x2) + 16x) - 12 = 0

STEP

2

:

Checking for a perfect cube

2.1 x3-7x2+16x-12 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-7x2+16x-12

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: x3-7x2

Group 2: 16x-12

Pull out from each group separately :

Group 1: (x-7) • (x2)

Group 2: (4x-3) • (4)