Question

if x=7+root5 then find the value of x+1÷x
its urgent guys don't seem.abswer will be reported ​

Answer 1

☞Refer to the above attachment mate :)

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Answer 2

Step-by-step explanation:

$x = 7 + \sqrt{5}$

$\frac{x + 1}{x}$

$\frac{7 + \sqrt{5} + 1 }{7 + \sqrt{5} }$

$\frac{7 + \sqrt{5} + 1}{ 7 + \sqrt{5} } \times \frac{7 - \sqrt{5} }{7 - \sqrt{5} }$

$\frac{ {7}^{2} - 5 + 7 - \sqrt{5} }{ {7}^{2} - 5 }$

$\frac{51 - \sqrt{5} }{44}$

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