Question

If x-7/x = 6 then largest
possible value of x is. ​

Answer 1

Step-by-step explanation:

$\tt \dfrac{x-7}{x}=6$

$\implies \tt x-7=x \times 6$

$\implies \tt x-7=6x$

$\implies \sf -7=6x-x$

$\implies \sf -7=5x$

$\implies \sf x= - \dfrac{7}{5}$

Hope it helps

Answer 2

Answer:

The answer is -

$\frac{-1}{35}$

Step-by-step explanation:

To find the largest possible value of x in $\frac{x-7}{x}$ = 6

Follow the rules of linear equation

As

$\frac{x-7}{x}$ = $\frac{x}{x} - \frac{7}{x}$

So,

$\frac{x-7}{x}$ = 6

$\frac{x}{x} - \frac{7}{x}$ = 6

As x ÷ x is 1

So,

$\frac{x}{x} - \frac{7}{x}$ = 6

1 - $\frac{7}{x}$ = 6

$\frac{-7}{x}$ = 6 - 1

    = 5

$\frac{-1}{x}$ = 5 X 7

    = 35

-$x$  =  $\frac{1}{35}$

$x$  =  $\frac{-1}{35}$

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