if x= 7y+3 and z= 49y^2 then what is 'z' in term of x?
Answers
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Heya !!
X = 7Y + 3
7Y = ( X - 3 )
Y = ( X - 3 ) / 7
And,
Z = 49Y²
Z = 49 × ( X - 3 /7)²
=> 49 × ( X - 3 )² / 49
=> ( X - 3 )²
=> X² + (3)² - 2 × X × 3
=> X² + 9 - 6X
=> X² - 6X + 9.
Z = X² - 6X + 9
Hence,
Value of Z in terms of X = X² - 6X + 9.
X = 7Y + 3
7Y = ( X - 3 )
Y = ( X - 3 ) / 7
And,
Z = 49Y²
Z = 49 × ( X - 3 /7)²
=> 49 × ( X - 3 )² / 49
=> ( X - 3 )²
=> X² + (3)² - 2 × X × 3
=> X² + 9 - 6X
=> X² - 6X + 9.
Z = X² - 6X + 9
Hence,
Value of Z in terms of X = X² - 6X + 9.
waleedqureshi2pc7oe3:
but book is showing (x-3)^2/7 is correct answer
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