If X =8.00± 0.04 CM and Y =4.00±0.04cm then x/y should be expressed as?
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Answer ⇒ X/Y = 2.00 ± 0.03 cm.
Explanation ⇒ X = 8.00 ± 0.04
Y = 4.00 ± 0.04
Now, X/Y = 8.00/4.00
∴ X/Y = 2.00
Let X/Y = D
But, We need to find the error in X/Y.
Relative error in D or X/Y = ΔX/X + ΔY/Y
∴ ΔD/D = 0.04/8 + 0.04/4
∴ Relative error in D or X/Y = 0.12/8 = 0.015
∴ ΔD = 0.03
∴ D = X/Y = 2.00 ± 0.03 cm.
Hope it helps.
amitthakur31:
it really helped
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