If x, 8, 11, y are the consecutive terms of an Arithmetic progression.
The values of ‘x’ and ‘y’ are respectively equal to
A. 6 and 13 B. 4 and 15
C. 3 and 16 D. 5 and 14
Answers
Answer:
Answer is D
Step-by-step explanation:
5 and 14 option D
The values of ‘x’ and ‘y’ are respectively equal to D. 5 and 14
Given :
x, 8, 11, y are the consecutive terms of an Arithmetic progression
To find :
The values of ‘x’ and ‘y’ are respectively equal to
A. 6 and 13
B. 4 and 15
C. 3 and 16
D. 5 and 14
Solution :
Step 1 of 2 :
Find common difference
Here it is given that x, 8, 11, y are the consecutive terms of an Arithmetic progression
First term = x
Second Term = 8
Third term = 11
Fourth term = y
We know that for a given arithmetic progression Common difference is the difference between two consecutive terms in the arithmetic progression
So the common difference
= d
= Third term - Second Term
= 14 - 11
= 3
Step 2 of 2 :
Find the value of x and y
First term
= x
= Second Term - Common Difference
= 8 - 3
= 5
Second Term = 8
Third term = 11
Fourth term
= y
= Third term + Common Difference
= 11 + 3
= 14
So the values of ‘x’ and ‘y’ are 5 and 14 respectively
Hence the correct option is D. 5 and 14
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