if X— {8power n - 7n-1/n €N}and Y–{49 ( n-1) /n€N} then
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Answer:
Correct option is
A
X⊂Y
Given, X=8
n
−7n−1
=(1+7)
n
−7n−1
=1+7n+
2
n(n−1)
7
2
+....+7
n
−7n−1
=
2
n(n−1)
7
2
+....+7
n
=49[
2
n(n−1)
+....+7
n−2
]
Hence, the set X will be some specific multiples of 49.
Y=49(n−1)
Hence, the set Y will be all multiples of 49. So, it will contain the elements of X too.
So, X⊂Y
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