if x=9-4√5,then find the value of x^3-1/x^3
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Answered by
34
Hi ,
x = 9 - 4√5 ----( 1 )
1/x = 1 / ( 9 - 4√5 )
= ( 9 + 4√5 ) / [ ( 9 - 4√5 ) ( 9 + 4√5 )
= ( 9 + 4√5 ) / [ 9² - ( 4√5 )² ]
= ( 9 + 4√5 ) / [ 81 - 80 ]
= 9 + 4√5 ---( 2 )
x - 1/x = 9 - 4√5 - ( 9 + 4√5 )
= 9 - 4√5 - 9 - 4√5
= -8√5 ---( 3 )
x³ - 1/x³ = ( x - 1/x )³ - 3( x - 1/x )
= ( - 8√5 )³ - 3 × ( - 8√5 )
= ( -8√5 ) [ ( - 8√5 )² - 3 ]
= ( -8√5 ) [ 320 - 3 ]
= ( -8√5 ) × 317
= - 2536√5
I hope this helps you.
:(
x = 9 - 4√5 ----( 1 )
1/x = 1 / ( 9 - 4√5 )
= ( 9 + 4√5 ) / [ ( 9 - 4√5 ) ( 9 + 4√5 )
= ( 9 + 4√5 ) / [ 9² - ( 4√5 )² ]
= ( 9 + 4√5 ) / [ 81 - 80 ]
= 9 + 4√5 ---( 2 )
x - 1/x = 9 - 4√5 - ( 9 + 4√5 )
= 9 - 4√5 - 9 - 4√5
= -8√5 ---( 3 )
x³ - 1/x³ = ( x - 1/x )³ - 3( x - 1/x )
= ( - 8√5 )³ - 3 × ( - 8√5 )
= ( -8√5 ) [ ( - 8√5 )² - 3 ]
= ( -8√5 ) [ 320 - 3 ]
= ( -8√5 ) × 317
= - 2536√5
I hope this helps you.
:(
Answered by
0
Answer:
=(9+4√5)/(9-4√5)(9+4√5)
=(9+4√5)/[9²-(4√5)]
=(9+4√5)/(81-80)
=(9+4√5)
=x-1/x=9-4√5-(9+4√5)
=9-4√5- 9-4√5
=-8√5
=x³-1/x³=(x-1/x)³-3(x-1/x)
=(-8√5)[(-8√5)²-3]
=(-8√5)(320-3)
=(-8√5)*317
=2536√5
Step-by-step explanation:
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